# We have a boolean function

• Defined as F=A’B’C’+A’B’C+AB’C’+AB’C

According to Boolean Identitities and laws:

Using the rules A+A’=1 and A+A=A we get

F=A’B’(C’+C)+AB’(C’+C)

F=A’B’(1)+AB’(1) using the rule A(1)=A

F=A’B’+AB’

Using the distributive rule A(B+C)= AB+BC

B’(A’+A) Using the A+A’=1 rule

B’(1) Using the rule A(1)=A

Final simplified expression is B’

The logic gate diagram for this function would be:

• @Tina The question was to simplify the boolean expression, F=A’B’C’+A’B’C+AB’C’+AB’C

then draw a logic gate diagram for F=A’B’C’+A’B’C+AB’C’+AB’C

• What is the question