the sum of both digits in a two digit number is 7 . the number obtained by interchanging the digits exceeds the original number by 27 . find the 2 digit number .
twisty question but i solved it in class today b4 anybody else did
I don't know how you did it but here's how I did it,
suppose the unknown number be z and the tenth place value be x and the oneth place value be y
Hence, 10x + y = z
it is given that 10y + x = z - 27
if we subtract these two, the answer would be, 9x - 9y = 27
which is 9(x - y) = 27 => x - y = 3
x = y + 3
given that x + y = 7
substituting x, y + y + 3 = 7
2y + 3 = 7
2y = 4
y = 2
Hence, x = 2 + 3, X = 5
Hence z = 52
is that a little too long...
@nastasio yes. 52/25 is the correct answer
my first language is not englisch so im not sure if i understood it correctly, but maybe the answer is 25 ?
@sir-devil yeah 25 is the correct answer